Distance from Winfield to Aleksandrovac
The shortest distance (air line) between Winfield and Aleksandrovac is 5,640.97 mi (9,078.26 km).
How far is Winfield from Aleksandrovac
Winfield is located in Kansas, United States within 37° 16' 26.4" N -97° 2' 60" W (37.2740, -96.9500) coordinates. The local time in Winfield is 22:49 (17.11.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 05:49 (18.11.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,640.97 miles which is equal to 9,078.26 km.
Winfield, Kansas, United States
Related Distances from Winfield
Aleksandrovac, Rasinska oblast, Serbia