Distance from Westerville to Walnut
The shortest distance (air line) between Westerville and Walnut is 1,958.09 mi (3,151.25 km).
How far is Westerville from Walnut
Westerville is located in Ohio, United States within 40° 7' 26.76" N -83° 4' 44.4" W (40.1241, -82.9210) coordinates. The local time in Westerville is 17:33 (22.12.2025)
Walnut is located in California, United States within 34° 2' 0.24" N -118° 8' 26.52" W (34.0334, -117.8593) coordinates. The local time in Walnut is 14:33 (22.12.2025)
The calculated flying distance from Walnut to Walnut is 1,958.09 miles which is equal to 3,151.25 km.
Westerville, Ohio, United States
Related Distances from Westerville
Walnut, California, United States