Distance from Waynesboro to Sveti Ivan Zelina
The shortest distance (air line) between Waynesboro and Sveti Ivan Zelina is 4,614.50 mi (7,426.31 km).
How far is Waynesboro from Sveti Ivan Zelina
Waynesboro is located in Virginia, United States within 38° 4' 2.64" N -79° 5' 54.96" W (38.0674, -78.9014) coordinates. The local time in Waynesboro is 21:29 (07.08.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 03:29 (08.08.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,614.50 miles which is equal to 7,426.31 km.
Waynesboro, Virginia, United States
Related Distances from Waynesboro
Sveti Ivan Zelina, Zagrebačka županija, Croatia