Distance from Waunakee to Drobeta-Turnu Severin
The shortest distance (air line) between Waunakee and Drobeta-Turnu Severin is 5,071.77 mi (8,162.22 km).
How far is Waunakee from Drobeta-Turnu Severin
Waunakee is located in Wisconsin, United States within 43° 10' 58.44" N -90° 33' 19.08" W (43.1829, -89.4447) coordinates. The local time in Waunakee is 18:56 (15.11.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 02:56 (16.11.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 5,071.77 miles which is equal to 8,162.22 km.
Waunakee, Wisconsin, United States
Related Distances from Waunakee
Drobeta-Turnu Severin, Mehedinţi, Romania