Distance from Waunakee to Aleksandrovac
The shortest distance (air line) between Waunakee and Aleksandrovac is 5,072.90 mi (8,164.04 km).
How far is Waunakee from Aleksandrovac
Waunakee is located in Wisconsin, United States within 43° 10' 58.44" N -90° 33' 19.08" W (43.1829, -89.4447) coordinates. The local time in Waunakee is 11:52 (16.11.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 18:52 (16.11.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,072.90 miles which is equal to 8,164.04 km.
Waunakee, Wisconsin, United States
Related Distances from Waunakee
Aleksandrovac, Rasinska oblast, Serbia