Distance from Waukegan to Vaux-le-Penil
The shortest distance (air line) between Waukegan and Vaux-le-Penil is 4,144.65 mi (6,670.17 km).
How far is Waukegan from Vaux-le-Penil
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 23:57 (29.08.2025)
Vaux-le-Penil is located in Seine-et-Marne, France within 48° 31' 35.04" N 2° 40' 55.92" E (48.5264, 2.6822) coordinates. The local time in Vaux-le-Penil is 06:57 (30.08.2025)
The calculated flying distance from Vaux-le-Penil to Vaux-le-Penil is 4,144.65 miles which is equal to 6,670.17 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Vaux-le-Penil, Seine-et-Marne, France