Distance from Waukegan to San Severino Marche
The shortest distance (air line) between Waukegan and San Severino Marche is 4,767.27 mi (7,672.17 km).
How far is Waukegan from San Severino Marche
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 14:21 (11.11.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 21:21 (11.11.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,767.27 miles which is equal to 7,672.17 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
San Severino Marche, Macerata, Italy