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      Distance from Waukegan to San Pancrazio Salentino

      The shortest distance (air line) between Waukegan and San Pancrazio Salentino is 5,075.66 mi (8,168.48 km).

      How far is Waukegan from San Pancrazio Salentino

      Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 23:06 (11.11.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 06:06 (12.11.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 5,075.66 miles which is equal to 8,168.48 km.

      Waukegan, Illinois, United States

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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino