Distance from Waukegan to Drawsko Pomorskie
The shortest distance (air line) between Waukegan and Drawsko Pomorskie is 4,422.84 mi (7,117.87 km).
How far is Waukegan from Drawsko Pomorskie
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 04:17 (18.11.2025)
Drawsko Pomorskie is located in Szczecinecko-pyrzycki, Poland within 53° 31' 59.88" N 15° 48' 0" E (53.5333, 15.8000) coordinates. The local time in Drawsko Pomorskie is 11:17 (18.11.2025)
The calculated flying distance from Drawsko Pomorskie to Drawsko Pomorskie is 4,422.84 miles which is equal to 7,117.87 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Drawsko Pomorskie, Szczecinecko-pyrzycki, Poland