Distance from Waukegan to Aleksandrow Lodzki
The shortest distance (air line) between Waukegan and Aleksandrow Lodzki is 4,611.39 mi (7,421.32 km).
How far is Waukegan from Aleksandrow Lodzki
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 19:50 (17.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:50 (18.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,611.39 miles which is equal to 7,421.32 km.
Waukegan, Illinois, United States
Related Distances from Waukegan
Aleksandrow Lodzki, Łódzki, Poland