Distance from Waukee to Aleksandrow Kujawski
The shortest distance (air line) between Waukee and Aleksandrow Kujawski is 4,777.24 mi (7,688.22 km).
How far is Waukee from Aleksandrow Kujawski
Waukee is located in Iowa, United States within 41° 35' 54.6" N -94° 6' 47.16" W (41.5985, -93.8869) coordinates. The local time in Waukee is 00:53 (14.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 07:53 (14.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,777.24 miles which is equal to 7,688.22 km.
Related Distances from Waukee
Aleksandrow Kujawski, Włocławski, Poland