Distance from Washougal to San Pietro in Casale
The shortest distance (air line) between Washougal and San Pietro in Casale is 5,588.57 mi (8,993.94 km).
How far is Washougal from San Pietro in Casale
Washougal is located in Washington, United States within 45° 34' 57" N -123° 39' 17.64" W (45.5825, -122.3451) coordinates. The local time in Washougal is 10:32 (03.09.2025)
San Pietro in Casale is located in Bologna, Italy within 44° 42' 0" N 11° 24' 0" E (44.7000, 11.4000) coordinates. The local time in San Pietro in Casale is 19:32 (03.09.2025)
The calculated flying distance from San Pietro in Casale to San Pietro in Casale is 5,588.57 miles which is equal to 8,993.94 km.
Washougal, Washington, United States
Related Distances from Washougal
San Pietro in Casale, Bologna, Italy