Distance from Warrensville Heights to Koekelberg
The shortest distance (air line) between Warrensville Heights and Koekelberg is 3,924.66 mi (6,316.12 km).
How far is Warrensville Heights from Koekelberg
Warrensville Heights is located in Ohio, United States within 41° 26' 10.68" N -82° 28' 40.08" W (41.4363, -81.5222) coordinates. The local time in Warrensville Heights is 12:01 (08.10.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 18:01 (08.10.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,924.66 miles which is equal to 6,316.12 km.
Warrensville Heights, Ohio, United States
Related Distances from Warrensville Heights
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium