Distance from Warrensburg to Sveti Ivan Zelina
The shortest distance (air line) between Warrensburg and Sveti Ivan Zelina is 5,156.84 mi (8,299.14 km).
How far is Warrensburg from Sveti Ivan Zelina
Warrensburg is located in Missouri, United States within 38° 45' 45.72" N -94° 16' 26.4" W (38.7627, -93.7260) coordinates. The local time in Warrensburg is 11:44 (05.08.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 18:44 (05.08.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,156.84 miles which is equal to 8,299.14 km.
Warrensburg, Missouri, United States
Related Distances from Warrensburg
Sveti Ivan Zelina, Zagrebačka županija, Croatia