Distance from Walnut Park to Diekirch
The shortest distance (air line) between Walnut Park and Diekirch is 5,720.88 mi (9,206.87 km).
How far is Walnut Park from Diekirch
Walnut Park is located in California, United States within 33° 58' 5.52" N -119° 46' 40.8" W (33.9682, -118.2220) coordinates. The local time in Walnut Park is 15:03 (30.08.2025)
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 00:03 (31.08.2025)
The calculated flying distance from Diekirch to Diekirch is 5,720.88 miles which is equal to 9,206.87 km.
Walnut Park, California, United States
Related Distances from Walnut Park
Diekirch, Luxembourg, Luxembourg
Related Distances to Diekirch
Cities | Distance |
---|---|
Vianden to Diekirch | 5.06 mi (8.14 km) |
Mersch to Diekirch | 8.54 mi (13.75 km) |
Wiltz to Diekirch | 12.05 mi (19.39 km) |
Echternach to Diekirch | 12.43 mi (20.01 km) |
Clervaux to Diekirch | 13.71 mi (22.07 km) |
Redange-sur-Attert to Diekirch | 13.88 mi (22.33 km) |
Capellen to Diekirch | 17.16 mi (27.62 km) |
Luxembourg to Diekirch | 17.75 mi (28.57 km) |
Grevenmacher to Diekirch | 18.15 mi (29.22 km) |
Remich to Diekirch | 24.25 mi (39.03 km) |
Differdange to Diekirch | 26.67 mi (42.93 km) |
Dudelange to Diekirch | 26.79 mi (43.11 km) |
Esch-sur-Alzette to Diekirch | 26.83 mi (43.18 km) |