Distance from Wade Hampton to Dimitrovgrad
The shortest distance (air line) between Wade Hampton and Dimitrovgrad is 5,284.47 mi (8,504.54 km).
How far is Wade Hampton from Dimitrovgrad
Wade Hampton is located in South Carolina, United States within 34° 52' 55.56" N -83° 39' 59.04" W (34.8821, -82.3336) coordinates. The local time in Wade Hampton is 19:14 (07.08.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 01:14 (08.08.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,284.47 miles which is equal to 8,504.54 km.
Wade Hampton, South Carolina, United States
Related Distances from Wade Hampton
Dimitrovgrad, Pirotska oblast, Serbia