Distance from Villanueva de Arosa to Cesky Tesin
The shortest distance (air line) between Villanueva de Arosa and Cesky Tesin is 1,395.00 mi (2,245.04 km).
How far is Villanueva de Arosa from Cesky Tesin
Villanueva de Arosa is located in Pontevedra, Spain within 42° 33' 46.08" N -9° 10' 19.92" W (42.5628, -8.8278) coordinates. The local time in Villanueva de Arosa is 08:55 (31.07.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 08:55 (31.07.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 1,395.00 miles which is equal to 2,245.04 km.
Villanueva de Arosa, Pontevedra, Spain
Related Distances from Villanueva de Arosa
Cesky Tesin, Moravskoslezský kraj, Czechia