Distance from Vernon Hills to Asenovgrad
The shortest distance (air line) between Vernon Hills and Asenovgrad is 5,273.20 mi (8,486.40 km).
How far is Vernon Hills from Asenovgrad
Vernon Hills is located in Illinois, United States within 42° 14' 2.4" N -88° 2' 21.12" W (42.2340, -87.9608) coordinates. The local time in Vernon Hills is 13:05 (05.08.2025)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 21:05 (05.08.2025)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,273.20 miles which is equal to 8,486.40 km.
Vernon Hills, Illinois, United States