Distance from Twin Rivers to Alexandria
The shortest distance (air line) between Twin Rivers and Alexandria is 4,781.77 mi (7,695.52 km).
How far is Twin Rivers from Alexandria
Twin Rivers is located in New Jersey, United States within 40° 15' 47.16" N -75° 30' 29.88" W (40.2631, -74.4917) coordinates. The local time in Twin Rivers is 00:04 (17.11.2025)
Alexandria is located in Teleorman, Romania within 43° 58' 6.96" N 25° 19' 59.88" E (43.9686, 25.3333) coordinates. The local time in Alexandria is 07:04 (17.11.2025)
The calculated flying distance from Alexandria to Alexandria is 4,781.77 miles which is equal to 7,695.52 km.
Twin Rivers, New Jersey, United States
Related Distances from Twin Rivers
Alexandria, Teleorman, Romania