Distance from Tupelo to Sassenburg
The shortest distance (air line) between Tupelo and Sassenburg is 4,739.32 mi (7,627.20 km).
How far is Tupelo from Sassenburg
Tupelo is located in Mississippi, United States within 34° 16' 9.12" N -89° 16' 5.52" W (34.2692, -88.7318) coordinates. The local time in Tupelo is 21:47 (29.08.2025)
Sassenburg is located in Gifhorn, Germany within 52° 31' 0.12" N 10° 37' 59.88" E (52.5167, 10.6333) coordinates. The local time in Sassenburg is 04:47 (30.08.2025)
The calculated flying distance from Sassenburg to Sassenburg is 4,739.32 miles which is equal to 7,627.20 km.
Tupelo, Mississippi, United States