Distance from Tupelo to San Vito dei Normanni
The shortest distance (air line) between Tupelo and San Vito dei Normanni is 5,463.77 mi (8,793.08 km).
How far is Tupelo from San Vito dei Normanni
Tupelo is located in Mississippi, United States within 34° 16' 9.12" N -89° 16' 5.52" W (34.2692, -88.7318) coordinates. The local time in Tupelo is 23:27 (08.11.2025)
San Vito dei Normanni is located in Brindisi, Italy within 40° 39' 20.16" N 17° 42' 12.96" E (40.6556, 17.7036) coordinates. The local time in San Vito dei Normanni is 06:27 (09.11.2025)
The calculated flying distance from San Vito dei Normanni to San Vito dei Normanni is 5,463.77 miles which is equal to 8,793.08 km.
Tupelo, Mississippi, United States
Related Distances from Tupelo
San Vito dei Normanni, Brindisi, Italy