Distance from Tupelo to San Lazzaro di Savena
The shortest distance (air line) between Tupelo and San Lazzaro di Savena is 5,050.81 mi (8,128.49 km).
How far is Tupelo from San Lazzaro di Savena
Tupelo is located in Mississippi, United States within 34° 16' 9.12" N -89° 16' 5.52" W (34.2692, -88.7318) coordinates. The local time in Tupelo is 20:20 (08.11.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 03:20 (09.11.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 5,050.81 miles which is equal to 8,128.49 km.
Tupelo, Mississippi, United States
Related Distances from Tupelo
San Lazzaro di Savena, Bologna, Italy