Distance from Tupelo to San Cesareo
The shortest distance (air line) between Tupelo and San Cesareo is 5,208.66 mi (8,382.52 km).
How far is Tupelo from San Cesareo
Tupelo is located in Mississippi, United States within 34° 16' 9.12" N -89° 16' 5.52" W (34.2692, -88.7318) coordinates. The local time in Tupelo is 13:57 (08.11.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 20:57 (08.11.2025)
The calculated flying distance from San Cesareo to San Cesareo is 5,208.66 miles which is equal to 8,382.52 km.
Tupelo, Mississippi, United States