Distance from Tupelo to Peso da Regua
The shortest distance (air line) between Tupelo and Peso da Regua is 4,288.41 mi (6,901.53 km).
How far is Tupelo from Peso da Regua
Tupelo is located in Mississippi, United States within 34° 16' 9.12" N -89° 16' 5.52" W (34.2692, -88.7318) coordinates. The local time in Tupelo is 04:59 (16.11.2025)
Peso da Regua is located in Douro, Portugal within 41° 9' 55.08" N -8° 13' 24.96" W (41.1653, -7.7764) coordinates. The local time in Peso da Regua is 10:59 (16.11.2025)
The calculated flying distance from Peso da Regua to Peso da Regua is 4,288.41 miles which is equal to 6,901.53 km.
Tupelo, Mississippi, United States
Related Distances from Tupelo
Peso da Regua, Douro, Portugal