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      Distance from Tuckahoe to San Gregorio di Catania

      The shortest distance (air line) between Tuckahoe and San Gregorio di Catania is 4,835.44 mi (7,781.90 km).

      How far is Tuckahoe from San Gregorio di Catania

      Tuckahoe is located in Virginia, United States within 37° 35' 16.08" N -78° 24' 51.12" W (37.5878, -77.5858) coordinates. The local time in Tuckahoe is 11:23 (02.09.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 17:23 (02.09.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 4,835.44 miles which is equal to 7,781.90 km.

      Tuckahoe, Virginia, United States

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      Tuckahoe to Philadelphia (Pennsylvania)213.02 mi (342.83 km)
      Tuckahoe to Brooklyn (New York)287.63 mi (462.89 km)
      Tuckahoe to New York (New York)290.73 mi (467.88 km)
      Tuckahoe to Queens (New York)298.11 mi (479.77 km)
      Tuckahoe to Detroit (Michigan)441.47 mi (710.48 km)
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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania