Distance from Three Lakes to Drobeta-Turnu Severin
The shortest distance (air line) between Three Lakes and Drobeta-Turnu Severin is 5,585.60 mi (8,989.15 km).
How far is Three Lakes from Drobeta-Turnu Severin
Three Lakes is located in Florida, United States within 25° 38' 29.4" N -81° 35' 60" W (25.6415, -80.4000) coordinates. The local time in Three Lakes is 10:02 (17.11.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 17:02 (17.11.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 5,585.60 miles which is equal to 8,989.15 km.
Three Lakes, Florida, United States
Related Distances from Three Lakes
Drobeta-Turnu Severin, Mehedinţi, Romania