Distance from Three Lakes to Aleksandrow Lodzki
The shortest distance (air line) between Three Lakes and Aleksandrow Lodzki is 5,233.50 mi (8,422.51 km).
How far is Three Lakes from Aleksandrow Lodzki
Three Lakes is located in Florida, United States within 25° 38' 29.4" N -81° 35' 60" W (25.6415, -80.4000) coordinates. The local time in Three Lakes is 23:01 (13.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 05:01 (14.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,233.50 miles which is equal to 8,422.51 km.
Three Lakes, Florida, United States
Related Distances from Three Lakes
Aleksandrow Lodzki, Łódzki, Poland