Distance from Sveti Ivan Zelina to Oranienburg
The shortest distance (air line) between Sveti Ivan Zelina and Oranienburg is 488.47 mi (786.11 km).
How far is Sveti Ivan Zelina from Oranienburg
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 08:29 (14.08.2025)
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 08:29 (14.08.2025)
The calculated flying distance from Oranienburg to Oranienburg is 488.47 miles which is equal to 786.11 km.
Sveti Ivan Zelina, Zagrebačka županija, Croatia
Related Distances from Sveti Ivan Zelina
Oranienburg, Oberhavel, Germany