Distance from Superior to Sint-Andries
The shortest distance (air line) between Superior and Sint-Andries is 4,017.84 mi (6,466.09 km).
How far is Superior from Sint-Andries
Superior is located in Wisconsin, United States within 46° 41' 38.76" N -93° 55' 3.72" W (46.6941, -92.0823) coordinates. The local time in Superior is 09:52 (06.08.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 16:52 (06.08.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,017.84 miles which is equal to 6,466.09 km.
Superior, Wisconsin, United States
Related Distances from Superior
Sint-Andries, Arr. Brugge, Belgium