Distance from Summerfield to San Giovanni Rotondo
The shortest distance (air line) between Summerfield and San Giovanni Rotondo is 4,626.33 mi (7,445.36 km).
How far is Summerfield from San Giovanni Rotondo
Summerfield is located in Maryland, United States within 38° 54' 15.12" N -77° 7' 55.92" W (38.9042, -76.8678) coordinates. The local time in Summerfield is 03:44 (21.11.2025)
San Giovanni Rotondo is located in Foggia, Italy within 41° 42' 0" N 15° 43' 59.88" E (41.7000, 15.7333) coordinates. The local time in San Giovanni Rotondo is 09:44 (21.11.2025)
The calculated flying distance from San Giovanni Rotondo to San Giovanni Rotondo is 4,626.33 miles which is equal to 7,445.36 km.
Summerfield, Maryland, United States
Related Distances from Summerfield
San Giovanni Rotondo, Foggia, Italy