Distance from Suffolk to Aleksandrow Kujawski
The shortest distance (air line) between Suffolk and Aleksandrow Kujawski is 4,452.29 mi (7,165.26 km).
How far is Suffolk from Aleksandrow Kujawski
Suffolk is located in Virginia, United States within 36° 41' 43.08" N -77° 21' 36.72" W (36.6953, -76.6398) coordinates. The local time in Suffolk is 02:23 (13.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 08:23 (13.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,452.29 miles which is equal to 7,165.26 km.
Suffolk, Virginia, United States
Related Distances from Suffolk
Aleksandrow Kujawski, Włocławski, Poland