Distance from Spanaway to Lyaskovets
The shortest distance (air line) between Spanaway and Lyaskovets is 5,907.95 mi (9,507.93 km).
How far is Spanaway from Lyaskovets
Spanaway is located in Washington, United States within 47° 5' 52.44" N -123° 34' 36.12" W (47.0979, -122.4233) coordinates. The local time in Spanaway is 07:50 (05.08.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 17:50 (05.08.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,907.95 miles which is equal to 9,507.93 km.
Spanaway, Washington, United States
Related Distances from Spanaway
Lyaskovets, Veliko Tarnovo, Bulgaria