Distance from Spanaway to Diepenbeek
The shortest distance (air line) between Spanaway and Diepenbeek is 4,990.66 mi (8,031.69 km).
How far is Spanaway from Diepenbeek
Spanaway is located in Washington, United States within 47° 5' 52.44" N -123° 34' 36.12" W (47.0979, -122.4233) coordinates. The local time in Spanaway is 05:38 (01.08.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 14:38 (01.08.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,990.66 miles which is equal to 8,031.69 km.
Spanaway, Washington, United States
Related Distances from Spanaway
Diepenbeek, Arr. Hasselt, Belgium