Distance from Sokolow Podlaski to Wilmington Island
The shortest distance (air line) between Sokolow Podlaski and Wilmington Island is 5,005.91 mi (8,056.23 km).
How far is Sokolow Podlaski from Wilmington Island
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 20:29 (28.08.2025)
Wilmington Island is located in Georgia, United States within 32° 0' 11.88" N -81° 1' 29.28" W (32.0033, -80.9752) coordinates. The local time in Wilmington Island is 14:29 (28.08.2025)
The calculated flying distance from Wilmington Island to Wilmington Island is 5,005.91 miles which is equal to 8,056.23 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Wilmington Island, Georgia, United States