Distance from Sokolow Podlaski to Wilmington
The shortest distance (air line) between Sokolow Podlaski and Wilmington is 4,774.75 mi (7,684.22 km).
How far is Sokolow Podlaski from Wilmington
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 10:45 (26.08.2025)
Wilmington is located in North Carolina, United States within 34° 12' 35.64" N -78° 6' 48.24" W (34.2099, -77.8866) coordinates. The local time in Wilmington is 04:45 (26.08.2025)
The calculated flying distance from Wilmington to Wilmington is 4,774.75 miles which is equal to 7,684.22 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Wilmington, North Carolina, United States