Distance from Sokolow Podlaski to Wilkinsburg
The shortest distance (air line) between Sokolow Podlaski and Wilkinsburg is 4,517.99 mi (7,271.00 km).
How far is Sokolow Podlaski from Wilkinsburg
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 01:08 (30.08.2025)
Wilkinsburg is located in Pennsylvania, United States within 40° 26' 39.12" N -80° 7' 36.12" W (40.4442, -79.8733) coordinates. The local time in Wilkinsburg is 19:08 (29.08.2025)
The calculated flying distance from Wilkinsburg to Wilkinsburg is 4,517.99 miles which is equal to 7,271.00 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Wilkinsburg, Pennsylvania, United States