Distance from Sokolow Podlaski to Waterbury
The shortest distance (air line) between Sokolow Podlaski and Waterbury is 4,220.49 mi (6,792.23 km).
How far is Sokolow Podlaski from Waterbury
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 18:26 (25.08.2025)
Waterbury is located in Connecticut, United States within 41° 33' 29.52" N -74° 57' 50.04" W (41.5582, -73.0361) coordinates. The local time in Waterbury is 12:26 (25.08.2025)
The calculated flying distance from Waterbury to Waterbury is 4,220.49 miles which is equal to 6,792.23 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Waterbury, Connecticut, United States