Distance from Sokolow Podlaski to Warrensville Heights
The shortest distance (air line) between Sokolow Podlaski and Warrensville Heights is 4,522.40 mi (7,278.09 km).
How far is Sokolow Podlaski from Warrensville Heights
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 15:04 (25.08.2025)
Warrensville Heights is located in Ohio, United States within 41° 26' 10.68" N -82° 28' 40.08" W (41.4363, -81.5222) coordinates. The local time in Warrensville Heights is 09:04 (25.08.2025)
The calculated flying distance from Warrensville Heights to Warrensville Heights is 4,522.40 miles which is equal to 7,278.09 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Warrensville Heights, Ohio, United States