Distance from Sokolow Podlaski to Waimalu
The shortest distance (air line) between Sokolow Podlaski and Waimalu is 7,338.30 mi (11,809.85 km).
How far is Sokolow Podlaski from Waimalu
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 12:33 (25.08.2025)
Waimalu is located in Hawaii, United States within 21° 23' 28.68" N -158° 3' 55.8" W (21.3913, -157.9345) coordinates. The local time in Waimalu is 01:33 (25.08.2025)
The calculated flying distance from Waimalu to Waimalu is 7,338.30 miles which is equal to 11,809.85 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Waimalu, Hawaii, United States