Distance from Sokolow Podlaski to Summerlin South
The shortest distance (air line) between Sokolow Podlaski and Summerlin South is 5,808.94 mi (9,348.58 km).
How far is Sokolow Podlaski from Summerlin South
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 10:46 (24.08.2025)
Summerlin South is located in Nevada, United States within 36° 7' 27.12" N -116° 40' 3.36" W (36.1242, -115.3324) coordinates. The local time in Summerlin South is 01:46 (24.08.2025)
The calculated flying distance from Summerlin South to Summerlin South is 5,808.94 miles which is equal to 9,348.58 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Summerlin South, Nevada, United States