Distance from Sokolow Podlaski to Sioux Falls
The shortest distance (air line) between Sokolow Podlaski and Sioux Falls is 4,880.88 mi (7,855.01 km).
How far is Sokolow Podlaski from Sioux Falls
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 16:12 (23.08.2025)
Sioux Falls is located in South Dakota, United States within 43° 32' 22.56" N -97° 16' 8.04" W (43.5396, -96.7311) coordinates. The local time in Sioux Falls is 09:12 (23.08.2025)
The calculated flying distance from Sioux Falls to Sioux Falls is 4,880.88 miles which is equal to 7,855.01 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Sioux Falls, South Dakota, United States