Distance from Sokolow Podlaski to Severn
The shortest distance (air line) between Sokolow Podlaski and Severn is 4,474.23 mi (7,200.58 km).
How far is Sokolow Podlaski from Severn
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 15:57 (23.08.2025)
Severn is located in Maryland, United States within 39° 8' 7.8" N -77° 18' 15.84" W (39.1355, -76.6956) coordinates. The local time in Severn is 09:57 (23.08.2025)
The calculated flying distance from Severn to Severn is 4,474.23 miles which is equal to 7,200.58 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Severn, Maryland, United States