Distance from Sokolow Podlaski to Secaucus
The shortest distance (air line) between Sokolow Podlaski and Secaucus is 4,296.32 mi (6,914.26 km).
How far is Sokolow Podlaski from Secaucus
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 12:14 (23.08.2025)
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 06:14 (23.08.2025)
The calculated flying distance from Secaucus to Secaucus is 4,296.32 miles which is equal to 6,914.26 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Secaucus, New Jersey, United States