Distance from Sokolow Podlaski to Savage
The shortest distance (air line) between Sokolow Podlaski and Savage is 4,715.77 mi (7,589.29 km).
How far is Sokolow Podlaski from Savage
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 05:19 (23.08.2025)
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 22:19 (22.08.2025)
The calculated flying distance from Savage to Savage is 4,715.77 miles which is equal to 7,589.29 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Savage, Minnesota, United States