Distance from Sokolow Podlaski to San Agustin de Guadalix
The shortest distance (air line) between Sokolow Podlaski and San Agustin de Guadalix is 1,459.65 mi (2,349.08 km).
How far is Sokolow Podlaski from San Agustin de Guadalix
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 05:42 (26.07.2025)
San Agustin de Guadalix is located in Madrid, Spain within 40° 40' 41.16" N -4° 23' 6" W (40.6781, -3.6150) coordinates. The local time in San Agustin de Guadalix is 05:42 (26.07.2025)
The calculated flying distance from San Agustin de Guadalix to San Agustin de Guadalix is 1,459.65 miles which is equal to 2,349.08 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
San Agustin de Guadalix, Madrid, Spain