Distance from Sokolow Podlaski to Peekskill
The shortest distance (air line) between Sokolow Podlaski and Peekskill is 4,265.72 mi (6,865.01 km).
How far is Sokolow Podlaski from Peekskill
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 22:23 (21.08.2025)
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 16:23 (21.08.2025)
The calculated flying distance from Peekskill to Peekskill is 4,265.72 miles which is equal to 6,865.01 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Peekskill, New York, United States