Distance from Sokolow Podlaski to Patchogue
The shortest distance (air line) between Sokolow Podlaski and Patchogue is 4,259.56 mi (6,855.10 km).
How far is Sokolow Podlaski from Patchogue
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 19:28 (21.08.2025)
Patchogue is located in New York, United States within 40° 45' 43.56" N -74° 58' 53.4" W (40.7621, -73.0185) coordinates. The local time in Patchogue is 13:28 (21.08.2025)
The calculated flying distance from Patchogue to Patchogue is 4,259.56 miles which is equal to 6,855.10 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Patchogue, New York, United States