Distance from Sokolow Podlaski to Old Jamestown
The shortest distance (air line) between Sokolow Podlaski and Old Jamestown is 4,950.87 mi (7,967.65 km).
How far is Sokolow Podlaski from Old Jamestown
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 11:17 (21.08.2025)
Old Jamestown is located in Missouri, United States within 38° 50' 21.84" N -91° 42' 55.08" W (38.8394, -90.2847) coordinates. The local time in Old Jamestown is 04:17 (21.08.2025)
The calculated flying distance from Old Jamestown to Old Jamestown is 4,950.87 miles which is equal to 7,967.65 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
Old Jamestown, Missouri, United States