Distance from Sokolow Podlaski to North New Hyde Park
The shortest distance (air line) between Sokolow Podlaski and North New Hyde Park is 4,284.49 mi (6,895.21 km).
How far is Sokolow Podlaski from North New Hyde Park
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 02:35 (04.09.2025)
North New Hyde Park is located in New York, United States within 40° 44' 45.6" N -74° 18' 44.64" W (40.7460, -73.6876) coordinates. The local time in North New Hyde Park is 20:35 (03.09.2025)
The calculated flying distance from North New Hyde Park to North New Hyde Park is 4,284.49 miles which is equal to 6,895.21 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
North New Hyde Park, New York, United States