Distance from Sokolow Podlaski to North Lindenhurst
The shortest distance (air line) between Sokolow Podlaski and North Lindenhurst is 4,275.57 mi (6,880.86 km).
How far is Sokolow Podlaski from North Lindenhurst
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 09:08 (21.08.2025)
North Lindenhurst is located in New York, United States within 40° 42' 25.92" N -74° 36' 50.76" W (40.7072, -73.3859) coordinates. The local time in North Lindenhurst is 03:08 (21.08.2025)
The calculated flying distance from North Lindenhurst to North Lindenhurst is 4,275.57 miles which is equal to 6,880.86 km.
Sokolow Podlaski, Siedlecki, Poland
Related Distances from Sokolow Podlaski
North Lindenhurst, New York, United States